JavaScript-Developer-I Exam Dumps - Salesforce Developer Questions and Answers

The verified answer is A .

This constructor function runs when new Person() is called:

function Person() {

this.firstName = " John " ;

}

So this line:

const myFather = new Person();

creates an object like this:

{

firstName: " John "

}

Then the prototype is assigned a method named job:

Person.prototype = {

job: x = > " Developer "

};

Because myFather is created from Person, it can access properties and methods from Person.prototype.

So:

myFather.firstName

returns:

" John "

And:

myFather.job()

returns:

" Developer "

Therefore:

const result = myFather.firstName + " " + myFather.job();

becomes:

const result = " John " + " " + " Developer " ;

Final value:

" John Developer "

Option B is incorrect because job() returns " Developer " , not undefined.

Option C is incorrect because job exists on Person.prototype, so it is callable.

Option D is incorrect because firstName is assigned inside the constructor.

Therefore, the verified answer is A .

When pet1 = new Pet(); is created:

Inside Pet constructor:

Animal.call(this, size, type);

this.size = size;

this.name = name;

this.owner = owner;

Animal.call(this, size, type):

Sets this.type = type || ' Animal ' → ' Animal ' (because type is undefined).

Sets this.canTalk = false.

Then this.size, this.name, this.owner are set (to undefined since no args passed), but they do exist as properties .

So as own properties, pet1 has: type, canTalk, size, name, owner.

speak is defined on Animal.prototype, so pet1.speak exists by inheritance, but is not an own data property created in the constructor.

From the listed options, three important properties directly set by constructor logic and clearly used in behavior are:

canTalk

name

type

Thus, C, D, E.

The correct answer is C .

The typing errors in the options should be corrected as follows:

event.stopPropagation();

The stopPropagation() method is used to stop an event from continuing through the DOM event propagation path.

A click event normally goes through these phases:

Capturing phase → Target phase → Bubbling phase

Because the event listener is attached to the button:

el.addEventListener( " click " , printMessage, false);

the function printMessage receives the click event when the button is clicked. To stop the event from bubbling up to parent elements, the event object should be accepted as a parameter and stopPropagation() should be called inside the event handler.

Corrected code:

< html >

< body >

< div id= " logo " > Hello Logo! < /div >

< button id= " test " > Click me < /button >

< /body >

< script >

function printMessage(event) {

event.stopPropagation();

console.log( ' This is a test message ' );

}

let el = document.getElementById( ' test ' );

el.addEventListener( " click " , printMessage, false);

< /script >

< /html >

Why this is correct:

event.stopPropagation();

prevents the click event from moving upward to ancestor elements after the button’s handler runs.

Why the other options are incorrect:

A and B are incorrect because removeEventListener() is used to remove a previously registered event listener. It does not stop event bubbling for the current event.

D is incorrect because stopPropagation() should be called inside the active event handler that receives the event object. In this case, that function is:

printMessage(event)

Therefore, the verified answer is C .

The correct answer is D .

Semantic versioning usually follows this format:

MAJOR.MINOR.PATCH

For the version:

1.1.3

The parts are:

1 = MAJOR

1 = MINOR

3 = PATCH

A package version should be updated based on the type of change:

MAJOR version changes when there are breaking changes.

MINOR version changes when new features are added in a backward-compatible way.

PATCH version changes when backward-compatible bug fixes are added.

The question says the developer added new features that do not break backward compatibility . That means the minor version should increase.

Starting version:

1.1.3

Increase the minor version from 1 to 2, and reset the patch version to 0:

1.2.0

Why the other options are incorrect:

A. 1.2.3 is incorrect because when the minor version increases, the patch version should reset to 0.

B. 1.1.4 is incorrect because that would represent a patch update, usually for bug fixes, not new features.

C. 2.0.0 is incorrect because that would represent a major version update, usually for breaking changes.

D. 1.2.0 is correct because it represents a backward-compatible feature release.

Therefore, the verified answer is D .